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A Scientist Has Two Solutions

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A scientist has 2 acid solutions: Artesia, which is a 70% acid solution, and Borromeo, which is a 20% acrid solution.

(a) Find the amount of Artesia (in mL) that must be added to 500 mL of Borromeo order to produce a 60% acid solution.

(b) Detect the amount of Artesia and Borromeo (in mL) that can exist combined in order to form a 100 mL solution that is $55\%$ acid.

(c) Does in that location exist a combination of Artesia and Borromeo that is 80% acid?

Please help! give thanks y'all then much! ✪ ω ✪

Guest Oct 10, 2020
edited by GuestOct 10, 2020

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 #ane
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a ) Permit the volume required exist five .

v ten .seven + 500 x .2 / ( 5 + 500 ) = .vii

.2 five + 250 = .half dozen v + 180

.1 5 = 200

v = 2000 mL

b )

Let the volume of solution Artesia  required be 5 . The volume of solution of Borromeo required will be 100 - v

v x .7 + ( 100 - 5 ) 10 .2 / 100 = .55

.6 5 + 20 - .7 5 = 55

.v v = xx

v = 40 mL

volume of solution Borromeo = 60 mL .

c )

It is not possible because 90 % is more than seventy % the concentration of solution Artesia . Any mixture will have concentration less than 70 % .

Guest Oct ten, 2020
 #2
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tThis is my explanation in image class. It has been explained clearly.

Guest October 17, 2020

thirteen Online Users

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A Scientist Has Two Solutions,

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